Array.prototype.map(parseInt) tricky question

When I ran the following JS

['1', '7', '11'].map(parseInt);

1. ['1', '7', '11'].map(parseInt);

['1', '7', '11'].map(parseInt);

I surprisingly saw the result [1, NaN, 3] instead of [1, 7, 11]. But if we try parseFloat

['1', '7', '11'].map(parseFloat);

1. ['1', '7', '11'].map(parseFloat);

['1', '7', '11'].map(parseFloat);

the result is correct [1, 7, 11]
If we try the extended form of parseInt

['1', '7', '11'].map(i => parseInt(i));

1. ['1', '7', '11'].map(i => parseInt(i));

['1', '7', '11'].map(i => parseInt(i));

we get the proper outcome as well.

So why is it so messy with the short parseInt?